C Tutorial for Beginnersbillmartinn wrote: I want to learn C & C++ but I do not know where to start.
Then you may not have made the best choice there. Most of us here are not programmers. Aren't there any forums for programmers and people who want to become one?billmartinn wrote: ⤴Tue Sep 14, 2021 9:42 am I have just joined this forum to get an answer of my question.
I suggest reading this thread Wanting to learn 'C' but gcc not installing as there is a discussion of why learning python might be a better choice than learning C.billmartinn wrote: ⤴Tue Sep 14, 2021 9:42 amI want to learn C & C++ but I do not know where to start.
I wrote some stuff in Basic 40 years ago but I'd rate my programming skills to be very poor. I'm starting to study Python, as suggested elsewhere in this thread , as I suspect the learning curve to be quite a bit more gentle. I'd think with some basic grasps of programming under the belt, it will be much easier to learn other programming languages
. However, I have *never* read a programming book from cover to cover before starting to do my task. I read the basics and start implementing as soon as I am confident enough to be able to do something.To start the application you use following syntax:The program shall take an argument telling how many bytes per row are displayed and another argument for how many lines are displayed out. The program always reads from the beginning of the file, for this excersise.
Wherehextype.exe -i <filename> [-l <linecount>] [-b <bytes_per_row>]
Desired output format:-i defines the input file, binary or text, whatever
-l defines how many lines are displayed. Optional. if omitted displays the whole file
-b defines how many bytes per row are displayed. Optional, if omitted displays 16 bytes per row.
Code: Select all
00000000 : 00 01 02 03 04 05 06 07 08 09 0a 0b 0c 0d 0e 0f : ................
00000010 : 20 21 22 23 24 25 26 27 28 29 2a 2b 2c 2d 2e 2f : !"#$%&'()*+,-./
00000020 : 30 31 32 41 42 43 61 62 63 64 65 66 67 68 69 6a : 012ABCabcdefghij
So as to emphasize my "get something done" remark; below is a short and quite to the point Python implementation of that specification. That print() statement requires a lot more code in e.g. C and error handling as to e.g. open/read can moreover simply be left to Python.
Code: Select all
#!/usr/bin/env python3
import argparse
import string
parser = argparse.ArgumentParser()
parser.add_argument('-i', required=True, metavar='<filename>')
parser.add_argument('-l', type=int, default=float('inf'), metavar='<linecount>')
parser.add_argument('-b', type=int, default=16, metavar='<bytes_per_row>')
args = parser.parse_args()
p = [ ord(c) for c in string.digits + string.ascii_letters + string.punctuation + ' ' ]
f = open(args.i, 'rb')
o = 0
while args.l > 0:
d = f.read(args.b)
n = len(d)
if n == 0:
break
print(('{:08x} : ' + n * '{:02x} '
+ (args.b - n) * ' '
+ ': '
+ n * '{:c}').format(o, *d, *[c if c in p else ord('.') for c in d]))
if n < args.b:
break
o += args.b
args.l -= 1
f.close()
Seems like a chore and tedious and long to do at first, but with time and experience you do it in your head automatically in a matter of seconds.Step 1: Start
Step 2: Declare Variable n, fact, i
Step 3: Read number from User
Step 4: Initialize Variable fact=1 and i=1
Step 5: Repeat Until i<=number
5.1 fact=fact*i
5.2 i=i+1
Step 6: Print fact
Step 7: Stop
Terminal - zsh wrote: ╭─legacy@forums.linuxmint.com
╰─➜ _
I'll note that this is very much not the case. Python is a serious, full and complete programming language and any complexity you'd not deal with in Python was, apparently then, not al that inevitable. Python supports multiple programming paradigms -- plain old procedural, object-oriented, (some) functional -- and may be considered a super-set of many other languages in that sense and others, certainly of C. What you "miss out on" is e.g. latter's manual memory management but try and find any modern not garbage-collected language. I.e., "miss out on" something in the end not inevitable at all.
